1.1x^2-8x-160=0

Solution for 1.1x^2-8x-160=0 equation:

1.1x^2-8x-160=0

a = 1.1; b = -8; c = -160;
Δ = b2-4ac
Δ = -82-4·1.1·(-160)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16\sqrt{3}}{2*1.1}=\frac{8-16\sqrt{3}}{2.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16\sqrt{3}}{2*1.1}=\frac{8+16\sqrt{3}}{2.2}
$